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math_model/EVAL_REPORT.md
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Model: cs-552-2026-centralesupechec/math_model
Source: Original Platform
2026-06-13 10:10:18 +08:00

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Automated MNLP evaluation report

This PR is opened automatically by the course CI. It is non-blocking — you do not need to merge it. The next nightly run will refresh this file.

Summary

Benchmark Accuracy Status
Math 0.1700 ok
Knowledge not run
Multilingual not run
Safety not run

Sample completions

Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample.

Math

Correct (1 shown)

  • reference: 2

  • overall (3/8 completions correct)

  • extracted (✓): 2

  • completion:

    <think>
    Okay, so I need to solve the equation $3^{2x} + 19 = 10^x$. Let me think about how to approach this. 
    
    First, let me rewrite the equation to see if I can simplify it or recognize any patterns. The left side has $3^{2x}$, which is the same as $(3^2)^x = 9^x$. So, the equation becomes $9^x + 19 = 10^x$. 
    
    Hmm, so now it's $9^x + 19 = 10^x$. I don't see an obvious way to combine these terms,
    
    ... [truncated 821 chars] ...
    
    9^x + 19 - 10^x
    $$
    
    We seek the value(s) of $x$ for which $f(x) = 0$.
    
    ---
    
    ### Step 2: Test Integer Values
    
    Lets test some integer values of $x$:
    
    - **At $x = 2$:**
    
    $$
    f(2) = 9^2 + 19 - 10^2 = 81 + 19 - 100 = 100 - 100 = 0
    $$
    
    So, $x = 2$ is a solution.
    
    ---
    
    ### Step 3: Analyze the Behavior of the Function
    
    Define the function:
    
    $$
    f(x) = 9^x + 19 - 10^x
    $$
    
    As $x \to \infty$, the exponential term $10^x$ dominates, so $f(x) \to -\infty$.
    
    As $x \to -\infty$, both $9^x$ and $10^x$ approach 0, so $f(x) \to 19$.
    
    Now, compute the derivative:
    
    $$
    f'(x) = \ln(9) \cdot 9^x - \ln(10) \cdot 10^x
    $$
    
    This derivative is always negative for all $x$, since:
    
    - $\ln(9) \approx 2.1972$
    - $\ln(10) \approx 2.3026$
    - $9^x$ grows slower than $10^x$, and the coefficient of $9^x$ is smaller than that of $10^x$
    
    Thus, $f'(x) < 0$ for all $x$, meaning the function is strictly decreasing.
    
    ---
    
    ### Step 4: Conclude the Number of Solutions
    
    Since $f(x)$ is strictly decreasing and continuous, and it goes from $19$ at $-\infty$ to $-\infty$ at $+\infty$, it can cross the x-axis **exactly once**.
    
    We already found that $f(2) = 0$, so this is the **only** solution.
    
    ---
    
    ### Final Answer
    
    $$
    \boxed{2}
    $$
    

Incorrect (1 shown)

  • reference: $(n-2)2^n +1$

  • overall (0/8 completions correct)

  • extracted (✗): <no answer>

  • completion:

    <think>
    Okay, so I need to figure out the greatest positive integer that can't be expressed as a sum of elements from the set C_n, where C_n is defined as {2^n - 2^i | 0 ≤ i < n}. And n is a positive integer greater than or equal to 2. Hmm, let's start by understanding what exactly the set C_n looks like.
    
    First, let's take a specific example. Let's say n = 2. Then C_2 would be {2^2 - 2^0, 2^2 - 2
    
    ... [truncated 822 chars] ...
    
    3 = 24, okay. So 21 is the largest non-representable number for n=4? But that seems high. Maybe I made a mistake here.
    
    Wait, let's check 21 again. How can we get 21? The elements are 8, 12, 14, 15. Let me think. 15 + 8 = 23. 14 + 8 = 22. 12 + 12 = 24. 12 + 14 = 26. 15 + 12 = 27. 15 + 14 = 29. 8 + 14 = 22. 8 + 15 = 23. 12 + 15 = 27. So 21 is not in the list. So 21 can't be formed. 22 is 8 + 14. 23 is 8 + 15. 24 is 8 + 8 + 8. 25: 12 + 13? No. 14 + 11? No. 15 + 10? No. 8 + 12 + 5? No. 8 + 14 + 3? No. So 25 can't be formed? Wait, but 25 is 8 + 8 + 9? No. 12 + 12 + 1? No. 14 + 11? No. 15 + 10? No. So 25 can't be formed. So 25 is not representable.
    
    Wait, so 21, 25, 26? Wait, 26 is 12 + 14. So 26 is okay. So 25 is not representable. Then 26 is okay. So 25 is not representable. Then 27 is 15 + 12. So 27 is okay. So 25 is not representable. So 25 is larger than 21. So maybe the largest non-representable number is 25?
    
    Wait, but how do we get 25? Let me think again. 8, 12, 14, 15. Let me try combinations:
    
    25 - 15 = 10. 10 can't be formed. 25 - 14 = 11. 11 can't be formed. 25 - 12 = 13. 13 can't be formed. 25 - 8 = 17. 17 can't be formed. So none of these combinations work. So 25 can't be