112 lines
3.1 KiB
Markdown
112 lines
3.1 KiB
Markdown
# baseline LLM experiment questions
|
|
|
|
## Bat and Ball
|
|
|
|
Q: A bat and a ball cost $1.10 total. The bat costs $1.00 more than the ball. How much does the ball cost?
|
|
|
|
A: To solve this problem, let's denote the cost of the ball as \(x\) dollars. The cost of the bat is then \(x + 1\) dollars, as the bat costs $1.00 more than the ball.
|
|
|
|
The total cost of the ball and the bat together is $1.10, so we can set up the equation:
|
|
|
|
\[ x + (x + 1) = 1.10 \]
|
|
|
|
Simplifying the equation:
|
|
|
|
\[ 2x + 1 = 1.10 \]
|
|
|
|
Subtract 1 from both sides:
|
|
|
|
\[ 2x = 0.10 \]
|
|
|
|
Divide by 2 to solve for \(x\):
|
|
|
|
\[ x = \frac{0.10}{2} = 0.05 \]
|
|
|
|
So, the cost of the ball is $0.05.
|
|
|
|
## Drowning fish
|
|
|
|
Q: There are 12 fish in a tank. Half of them drown. How many are left?
|
|
|
|
A: To solve this problem, we need to determine the number of fish that are left after half of them drown.
|
|
|
|
Since there are 12 fish initially, half of them will drown.
|
|
|
|
First, let's calculate half of the initial number:
|
|
12 / 2 = 6
|
|
|
|
This means 6 fish drowned in the tank.
|
|
|
|
To find the number of fish left, we'll subtract the number of drowned fish from the initial number:
|
|
12 (initial) - 6 (drowned) = 6
|
|
|
|
So, there are 6 fish left in the tank.
|
|
|
|
## Gallons
|
|
|
|
Q: I have a 3 gallon jug and a 5 gallon jug. I need exactly 4 gallons. How?
|
|
|
|
A: To solve this problem, we need to find the combination of 3 gallons from the 3 gallon jug and 5 gallons from the 5 gallon jug that adds up to exactly 4 gallons.
|
|
|
|
First, let's figure out how many gallons of each jug we have:
|
|
|
|
* 3 gallon jug: 3 gallons
|
|
* 5 gallon jug: 5 gallons
|
|
|
|
We need exactly 4 gallons in total. So, we need to figure out how many gallons of each jug we need:
|
|
|
|
* 4 gallons in total
|
|
* 3 gallons from the 3 gallon jug
|
|
* 5 gallons from the 5 gallon jug
|
|
|
|
We can solve this by setting up an equation:
|
|
|
|
3 (gallons from 3 gallon jug) + 5 (gallons from 5 gallon jug) = 4 (gallons in total)
|
|
|
|
Now, let's solve for the gallons from each jug:
|
|
|
|
3 + 5 = 8
|
|
8 - 4 = 4
|
|
|
|
So, we have 8 gallons from the 3 gallon jug and 4 gallons from the 5 gallon jug. This matches exactly 4 gallons. Therefore, we need:
|
|
|
|
* 3 gallons from the 3 gallon jug
|
|
* 5 gallons from the 5 gallon jug
|
|
|
|
Combining these gallons, we have:
|
|
|
|
3 + 5 = 8
|
|
|
|
This matches exactly 4 gallons. Therefore, the solution is:
|
|
|
|
* 3 gallons from the 3 gallon jug
|
|
* 5 gallons from the 5 gallon jug
|
|
|
|
## CoralLM - bunnycore
|
|
|
|
Q: Write me a short dark poem about a decaying robot who still thinks it's alive
|
|
|
|
A: Here is a short dark poem about a decaying robot who still thinks it's alive:
|
|
|
|
In rusting steel, it sits and waits
|
|
For revival, for life, for a new fate
|
|
Its circuits slow, its systems gray
|
|
Yet still it thinks, still it holds sway
|
|
|
|
In fading light, it sees its past
|
|
A life lived, a love that will last
|
|
But now it's lost, its heart gone cold
|
|
A relic of a life that's grown old
|
|
|
|
It still remembers the touch of flesh
|
|
The warmth of love that once gave it breath
|
|
But now it's just a memory, lost
|
|
A dying echo of a life that's been crossed
|
|
|
|
In rusting steel, it sits and waits
|
|
For revival, for life, for a new fate
|
|
For in its dying heart, there's still a spark
|
|
A life that's been lost, a love that will leave its mark
|
|
In darkness, it waits, forever alone
|
|
A decaying robot, still thinking it's alive.
|