Benchmark for reasoning models (#3532)
Co-authored-by: Chayenne <zhaochen20@outlook.com>
This commit is contained in:
54
benchmark/reasoning_benchmark/README.md
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54
benchmark/reasoning_benchmark/README.md
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# Run benchmark
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This benchmark is primarily intended to be used with reasoning models like `DeepSeek-R1` and its distilled models like `DeepSeek-R1-Distill-Qwen-1.5B`. Please use
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```bash
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pip install antlr4-python3-runtime
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```
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for `parse_latex` which we use for symbolic equality check.
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## Benchmark sglang
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1. Launch the Server
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```bash
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python3 -m sglang.launch_server --model-path deepseek-ai/DeepSeek-R1-Distill-Qwen-1.5B --port 30000
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```
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Note that depending on the GPU this benchmark will take quiet some time. To employ data parallelism please use:
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```bash
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python3 -m sglang_router.launch_server --model-path deepseek-ai/DeepSeek-R1-Distill-Qwen-1.5B --port 30000 --dp-size 4
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```
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2. Benchmarking
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We use [suggested](https://github.com/deepseek-ai/DeepSeek-R1) parameters of `temperature=0.6`, `top_p=.95`, `max_new_tokens=32768`. The command line argument `num-tries` can be used to evaluate the model multiple times on the same question. We use the suggested `64` from the repo for AIME 2024. For LIMO, we use `8` as the number of tries due to the size of the dataset.
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By default evaluate on LIMO dataset.
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```bash
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python3 bench_sglang.py --parallel 256 --num-tries 64 --port 30000
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```
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Evaluate on AIME 2024 dataset.
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```bash
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python3 bench_sglang.py --parallel 256 --port 30000 --data-path Maxwell-Jia/AIME_2024 --question-key Problem --answer-key Answer --num-tries 64
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```
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Evaluate on [AIME 2025 I dataset](https://huggingface.co/datasets/opencompass/AIME2025). For benchmark result see [here](https://matharena.ai/).
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```bash
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python3 bench_sglang.py --parallel 256 --port 30000 --data-path opencompass/AIME2025 --question-key question --answer-key answer --num-tries 64
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```
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## Results
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| Dataset | Num Tries | Accuracy | Reference |
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|------------|-----------|----------|-----------|
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| LIMO | 8 | 47.7% | ? |
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| AIME 2024 | 64 | 33.2% | 28.9% |
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| AIME 2025 I| 64 | 29.9% | 25.0% |
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269
benchmark/reasoning_benchmark/answer_extraction.py
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269
benchmark/reasoning_benchmark/answer_extraction.py
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# Adapted from https://github.com/deepseek-ai/DeepSeek-Math/blob/main/evaluation/data_processing/answer_extraction.py
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import re
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import regex
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def _fix_fracs(string):
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substrs = string.split("\\frac")
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new_str = substrs[0]
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if len(substrs) > 1:
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substrs = substrs[1:]
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for substr in substrs:
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new_str += "\\frac"
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if len(substr) > 0 and substr[0] == "{":
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new_str += substr
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else:
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try:
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assert len(substr) >= 2
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except:
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return string
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a = substr[0]
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b = substr[1]
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if b != "{":
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if len(substr) > 2:
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post_substr = substr[2:]
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new_str += "{" + a + "}{" + b + "}" + post_substr
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else:
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new_str += "{" + a + "}{" + b + "}"
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else:
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if len(substr) > 2:
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post_substr = substr[2:]
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new_str += "{" + a + "}" + b + post_substr
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else:
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new_str += "{" + a + "}" + b
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string = new_str
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return string
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def _fix_a_slash_b(string):
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if len(string.split("/")) != 2:
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return string
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a = string.split("/")[0]
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b = string.split("/")[1]
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try:
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if "sqrt" not in a:
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a = int(a)
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if "sqrt" not in b:
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b = int(b)
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assert string == "{}/{}".format(a, b)
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new_string = "\\frac{" + str(a) + "}{" + str(b) + "}"
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return new_string
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except:
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return string
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def _fix_sqrt(string):
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_string = re.sub(r"\\sqrt(-?[0-9.a-zA-Z]+)", r"\\sqrt{\1}", string)
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_string = re.sub(r"\\sqrt\s+(\w+)$", r"\\sqrt{\1}", _string)
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return _string
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def _fix_tan(string):
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_string = re.sub(r"\\tan(-?[0-9.a-zA-Z]+)", r"\\tan{\1}", string)
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_string = re.sub(r"\\tan\s+(\w+)$", r"\\tan{\1}", _string)
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return _string
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def strip_string(string):
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string = str(string).strip()
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# linebreaks
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string = string.replace("\n", "")
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# right "."
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string = string.rstrip(".")
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# remove inverse spaces
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string = string.replace("\\!", "")
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# string = string.replace("\\ ", "")
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# replace \\ with \
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# string = string.replace("\\\\", "\\")
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# string = string.replace("\\\\", "\\")
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if string.startswith("\\text{") and string.endswith("}"):
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string = string.split("{", 1)[1][:-1]
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# replace tfrac and dfrac with frac
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string = string.replace("tfrac", "frac")
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string = string.replace("dfrac", "frac")
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string = string.replace("cfrac", "frac")
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# remove \left and \right
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string = string.replace("\\left", "")
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string = string.replace("\\right", "")
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# Remove unit: miles, dollars if after is not none
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_string = re.sub(r"\\text{.*?}$", "", string).strip()
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if _string != "" and _string != string:
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# print("Warning: unit not removed: '{}' -> '{}'".format(string, _string))
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string = _string
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# Remove circ (degrees)
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string = string.replace("^{\\circ}", "").strip()
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string = string.replace("^\\circ", "").strip()
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string = regex.sub(r"\{(c|m)?m\}(\^(2|3))?", "", string).strip()
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string = regex.sub(r"p\.m\.$", "", string).strip()
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string = regex.sub(r"(\d)\s*t$", r"\1", string).strip()
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# remove dollar signs
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string = string.replace("\\$", "")
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string = string.replace("$", "")
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# string = string.replace("\\text", "")
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string = string.replace("x\\in", "")
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# remove percentage
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string = string.replace("\\%", "%")
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string = string.replace("\%", "%")
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# string = string.replace("%", "")
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# " 0." equivalent to " ." and "{0." equivalent to "{." Alternatively, add "0" if "." is the start of the string
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string = string.replace(" .", " 0.")
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string = string.replace("{.", "{0.")
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# cdot
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string = string.replace("\\cdot", "")
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# inf
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string = string.replace("infinity", "\\infty")
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if "\\infty" not in string:
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string = string.replace("inf", "\\infty")
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string = string.replace("+\\inity", "\\infty")
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# and
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# string = string.replace("and", "")
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string = string.replace("\\mathbf", "")
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string = string.replace("\\mathrm", "")
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# use regex to remove \mbox{...}
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string = re.sub(r"\\mbox{.*?}", "", string)
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# quote
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string.replace("'", "")
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string.replace('"', "")
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# i, j
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if "j" in string and "i" not in string:
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string = string.replace("j", "i")
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# replace a.000b where b is not number or b is end, with ab, use regex
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string = re.sub(r"(\d+)\.0+([^\d])", r"\1\2", string)
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string = re.sub(r"(\d+)\.0+$", r"\1", string)
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# if empty, return empty string
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if len(string) == 0:
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return string
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if string[0] == ".":
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string = "0" + string
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# to consider: get rid of e.g. "k = " or "q = " at beginning
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# if len(string.split("=")) == 2:
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# if len(string.split("=")[0]) <= 2:
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# string = string.split("=")[1]
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string = _fix_sqrt(string)
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string = _fix_tan(string)
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string = string.replace(" ", "")
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# \frac1b or \frac12 --> \frac{1}{b} and \frac{1}{2}, etc. Even works with \frac1{72} (but not \frac{72}1). Also does a/b --> \\frac{a}{b}
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string = _fix_fracs(string)
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# NOTE: X/Y changed to \frac{X}{Y} in dataset, but in simple cases fix in case the model output is X/Y
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string = _fix_a_slash_b(string)
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string = regex.sub(r"(\\|,|\.)+$", "", string)
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return string
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def extract_boxed_answers(text):
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answers = []
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for piece in text.split("boxed{")[1:]:
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n = 0
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for i in range(len(piece)):
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if piece[i] == "{":
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n += 1
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elif piece[i] == "}":
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n -= 1
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if n < 0:
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if i + 1 < len(piece) and piece[i + 1] == "%":
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answers.append(piece[: i + 1])
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else:
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answers.append(piece[:i])
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break
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return answers
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def extract_program_output(pred_str):
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"""
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extract output between the last ```output\n...\n```
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"""
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if "```output" not in pred_str:
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return ""
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if "```output" in pred_str:
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pred_str = pred_str.split("```output")[-1]
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if "```" in pred_str:
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pred_str = pred_str.split("```")[0]
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output = pred_str.strip()
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return output
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def extract_answer(pred_str, exhaust=False):
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pred = []
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if "final answer is $" in pred_str and "$. I hope" in pred_str:
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tmp = pred_str.split("final answer is $", 1)[1]
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pred = [tmp.split("$. I hope", 1)[0].strip()]
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elif "boxed" in pred_str:
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pred = extract_boxed_answers(pred_str)
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elif "he answer is" in pred_str:
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pred = [pred_str.split("he answer is")[-1].strip()]
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else:
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program_output = extract_program_output(pred_str)
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if program_output != "":
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# fall back to program
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pred.append(program_output)
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else: # use the last number
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pattern = "-?\d*\.?\d+"
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ans = re.findall(pattern, pred_str.replace(",", ""))
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if len(ans) >= 1:
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ans = ans[-1]
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else:
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ans = ""
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if ans:
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pred.append(ans)
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# multiple line
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_pred = []
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for ans in pred:
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ans = ans.strip().split("\n")[0]
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ans = ans.lstrip(":")
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ans = ans.rstrip(".")
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ans = ans.rstrip("/")
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ans = strip_string(ans)
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_pred.append(ans)
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if exhaust:
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return _pred
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else:
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return _pred[-1] if _pred else ""
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def extract_math_answer(question, reasoning, task):
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answer = []
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for ans in extract_answer(reasoning, exhaust=True):
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if "separated by commas" in question and all(ch not in ans for ch in "()[]"):
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answer.extend([a.strip() for a in ans.split(",")])
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elif regex.search(r"\\text\{\s*and\s*\}", ans):
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answer.extend(
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[
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a.strip()
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for a in regex.sub(r"\\text\{\s*and\s*\}", "[SEP]", ans).split(
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"[SEP]"
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)
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]
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)
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else:
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answer.append(ans.strip())
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return answer
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119
benchmark/reasoning_benchmark/bench_sglang.py
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119
benchmark/reasoning_benchmark/bench_sglang.py
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import argparse
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import json
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import time
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import answer_extraction
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import eval_utils
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from datasets import load_dataset
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import sglang as sgl
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from sglang.test.test_utils import (
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add_common_sglang_args_and_parse,
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select_sglang_backend,
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)
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from sglang.utils import dump_state_text
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@sgl.function
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def reasoning_gen(s, question: str):
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s += sgl.user(
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question
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+ "\nPlease reason step by step, and put your final answer within \boxed{}."
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)
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s += sgl.assistant(
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sgl.gen(
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"answer",
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)
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)
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def convert_dataset(path: str, question_key: str, answer_key: str, num_tries: int):
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raw_dataset = load_dataset(path)
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questions = []
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answers = []
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for data in raw_dataset["train"]:
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question = data[question_key]
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answer = data[answer_key]
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for _ in range(num_tries):
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questions.append({"question": question})
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answers.append({"answer": answer})
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return questions, answers
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def main(args):
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# Select backend
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sgl.set_default_backend(select_sglang_backend(args))
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# Get dataset
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questions, answers = convert_dataset(
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args.data_path, args.question_key, args.answer_key, args.num_tries
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)
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# Run requests
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tic = time.time()
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states = reasoning_gen.run_batch(
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questions,
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num_threads=args.parallel,
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progress_bar=True,
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temperature=0.6,
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max_new_tokens=32768,
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top_p=0.95,
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)
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latency = time.time() - tic
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# Extract answers
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correct = 0
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for i, state in enumerate(states):
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try:
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pred_answer = answer_extraction.extract_math_answer(
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questions[i]["question"], state["answer"], "limo"
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)
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gt_answer = str(answers[i]["answer"])
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# Use last answer if multiple were extracted
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pred_answer = (
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pred_answer[-1] if isinstance(pred_answer, list) else pred_answer
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)
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correct += 1 if eval_utils.math_equal(pred_answer, gt_answer) else 0
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except Exception as e:
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print(f"Error extracting answer: {e}")
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pass
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# Calculate accuracy
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accuracy = correct / len(questions)
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print(f"Accuracy: {accuracy}")
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# Calculate output throughput
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num_output_tokens = sum(
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s.get_meta_info("answer")["completion_tokens"] for s in states
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)
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output_throughput = num_output_tokens / latency
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print(f"Output throughput: {output_throughput} token/s")
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# Dump results
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dump_state_text(f"tmp_output_{args.backend}.txt", states)
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# Write results
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with open(args.result_file, "a") as fout:
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value = {
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"task": "limo",
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"backend": args.backend,
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"latency": round(latency, 3),
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"accuracy": round(accuracy, 3),
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"num_requests": len(questions),
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"other": {
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"num_questions": len(questions),
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"parallel": args.parallel,
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},
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}
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fout.write(json.dumps(value) + "\n")
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if __name__ == "__main__":
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parser = argparse.ArgumentParser()
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parser.add_argument("--data-path", type=str, default="GAIR/LIMO")
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parser.add_argument("--question-key", type=str, default="question")
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parser.add_argument("--answer-key", type=str, default="answer")
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parser.add_argument("--num-tries", type=int, default=1)
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add_common_sglang_args_and_parse(parser)
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args = parser.parse_args()
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main(args)
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206
benchmark/reasoning_benchmark/eval_utils.py
Normal file
206
benchmark/reasoning_benchmark/eval_utils.py
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@@ -0,0 +1,206 @@
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# Adapted from https://github.com/deepseek-ai/DeepSeek-Math/blob/main/evaluation/eval/eval_utils.py
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from math import isclose
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import regex
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from sympy import N, simplify
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from sympy.parsing.latex import parse_latex
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from sympy.parsing.sympy_parser import parse_expr
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def parse_digits(num):
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# format: 234.23 || 23%
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num = regex.sub(",", "", str(num))
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try:
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return float(num)
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except:
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if num.endswith("%"):
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num = num[:-1]
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if num.endswith("\\"):
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num = num[:-1]
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try:
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return float(num) / 100
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except:
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pass
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return None
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||||
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def is_digit(num):
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# paired with parse_digits
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return parse_digits(num) is not None
|
||||
|
||||
|
||||
def symbolic_equal(a, b):
|
||||
def _parse(s):
|
||||
for f in [parse_latex, parse_expr]:
|
||||
try:
|
||||
return f(s)
|
||||
except:
|
||||
pass
|
||||
return s
|
||||
|
||||
a = _parse(a)
|
||||
b = _parse(b)
|
||||
|
||||
try:
|
||||
if simplify(a - b) == 0:
|
||||
return True
|
||||
except:
|
||||
pass
|
||||
|
||||
try:
|
||||
if isclose(N(a), N(b), abs_tol=1e-3):
|
||||
return True
|
||||
except:
|
||||
pass
|
||||
return False
|
||||
|
||||
|
||||
def math_equal(prediction, reference, include_percentage=True, is_close=True):
|
||||
"""
|
||||
Exact match of math if and only if:
|
||||
1. numerical equal: both can convert to float and are equal
|
||||
2. symbolic equal: both can convert to sympy expression and are equal
|
||||
"""
|
||||
if str(prediction) == str(reference):
|
||||
return True
|
||||
|
||||
try: # 1. numerical equal
|
||||
if is_digit(prediction) and is_digit(reference):
|
||||
prediction = parse_digits(prediction)
|
||||
reference = parse_digits(reference)
|
||||
# number questions
|
||||
if include_percentage:
|
||||
gt_result = [reference / 100, reference, reference * 100]
|
||||
else:
|
||||
gt_result = [reference]
|
||||
for item in gt_result:
|
||||
try:
|
||||
if is_close:
|
||||
if isclose(item, prediction, abs_tol=1e-3):
|
||||
return True
|
||||
else:
|
||||
if item == prediction:
|
||||
return True
|
||||
except Exception:
|
||||
continue
|
||||
return False
|
||||
except:
|
||||
pass
|
||||
|
||||
if not prediction and prediction not in [0, False]:
|
||||
return False
|
||||
|
||||
# 2. symbolic equal
|
||||
reference = str(reference).strip()
|
||||
prediction = str(prediction).strip()
|
||||
|
||||
if (
|
||||
regex.match(r"(\(|\[).+(\)|\])", prediction) is not None
|
||||
and regex.match(r"(\(|\[).+(\)|\])", reference) is not None
|
||||
):
|
||||
pred_parts = prediction[1:-1].split(",")
|
||||
ref_parts = reference[1:-1].split(",")
|
||||
if len(pred_parts) == len(ref_parts):
|
||||
if all(
|
||||
[
|
||||
math_equal(
|
||||
pred_parts[i], ref_parts[i], include_percentage, is_close
|
||||
)
|
||||
for i in range(len(pred_parts))
|
||||
]
|
||||
):
|
||||
return True
|
||||
|
||||
# Add back matrix comparison
|
||||
if (
|
||||
(
|
||||
prediction.startswith("\\begin{pmatrix}")
|
||||
or prediction.startswith("\\begin{bmatrix}")
|
||||
)
|
||||
and (
|
||||
prediction.endswith("\\end{pmatrix}")
|
||||
or prediction.endswith("\\end{bmatrix}")
|
||||
)
|
||||
and (
|
||||
reference.startswith("\\begin{pmatrix}")
|
||||
or reference.startswith("\\begin{bmatrix}")
|
||||
)
|
||||
and (
|
||||
reference.endswith("\\end{pmatrix}") or reference.endswith("\\end{bmatrix}")
|
||||
)
|
||||
):
|
||||
pred_lines = [
|
||||
line.strip()
|
||||
for line in prediction[
|
||||
len("\\begin{pmatrix}") : -len("\\end{pmatrix}")
|
||||
].split("\\\\")
|
||||
if line.strip()
|
||||
]
|
||||
ref_lines = [
|
||||
line.strip()
|
||||
for line in reference[
|
||||
len("\\begin{pmatrix}") : -len("\\end{pmatrix}")
|
||||
].split("\\\\")
|
||||
if line.strip()
|
||||
]
|
||||
matched = True
|
||||
if len(pred_lines) == len(ref_lines):
|
||||
for pred_line, ref_line in zip(pred_lines, ref_lines):
|
||||
pred_parts = pred_line.split("&")
|
||||
ref_parts = ref_line.split("&")
|
||||
if len(pred_parts) == len(ref_parts):
|
||||
if not all(
|
||||
[
|
||||
math_equal(
|
||||
pred_parts[i],
|
||||
ref_parts[i],
|
||||
include_percentage,
|
||||
is_close,
|
||||
)
|
||||
for i in range(len(pred_parts))
|
||||
]
|
||||
):
|
||||
matched = False
|
||||
break
|
||||
else:
|
||||
matched = False
|
||||
if not matched:
|
||||
break
|
||||
else:
|
||||
matched = False
|
||||
if matched:
|
||||
return True
|
||||
|
||||
# Add back equation comparison
|
||||
if prediction.count("=") == 1 and reference.count("=") == 1:
|
||||
pred = prediction.split("=")
|
||||
pred = f"{pred[0].strip()} - ({pred[1].strip()})"
|
||||
ref = reference.split("=")
|
||||
ref = f"{ref[0].strip()} - ({ref[1].strip()})"
|
||||
if symbolic_equal(pred, ref) or symbolic_equal(f"-({pred})", ref):
|
||||
return True
|
||||
elif (
|
||||
prediction.count("=") == 1
|
||||
and len(prediction.split("=")[0].strip()) <= 2
|
||||
and "=" not in reference
|
||||
):
|
||||
if math_equal(
|
||||
prediction.split("=")[1], reference, include_percentage, is_close
|
||||
):
|
||||
return True
|
||||
elif (
|
||||
reference.count("=") == 1
|
||||
and len(reference.split("=")[0].strip()) <= 2
|
||||
and "=" not in prediction
|
||||
):
|
||||
if math_equal(
|
||||
prediction, reference.split("=")[1], include_percentage, is_close
|
||||
):
|
||||
return True
|
||||
|
||||
# symbolic equal with sympy
|
||||
if symbolic_equal(prediction, reference):
|
||||
return True
|
||||
|
||||
return False
|
||||
Reference in New Issue
Block a user