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Model: nv-community/Nemotron-Cascade-8B
Source: Original Platform

evaluation/data/mmlu/flan_cot_fewshot/mmlu_electrical_engineering.yaml

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+dataset_name: electrical_engineering
+description: '
+
+  The following are multiple choice questions (with answers) about electrical engineering.'
+fewshot_config:
+  sampler: first_n
+  samples:
+  - question: "A point pole has a strength of 4\u03C0 * 10^-4 weber. The force in newtons\
+      \ on a point pole of 4\u03C0 * 1.5 * 10^-4 weber placed at a distance of 10\
+      \ cm from it will be\n(A) 15 N. (B) 20 N. (C) 7.5 N. (D) 3.75 N."
+    target: "Let's think step by step. The force between two point poles is given\
+      \ by m_1m_2/(mu_0 4 \\pi r^2), in analogy to Coulomb\u2019s law. Plugging in\
+      \ the values given in the question, we calculate that the force is approximately\
+      \ 15 N. The answer is (A)."
+  - question: 'The coil of a moving coil meter has 100 turns, is 40 mm long and 30 mm
+      wide. The control torque is 240*10-6 N-m on full scale. If magnetic flux density
+      is 1Wb/m2 range of meter is
+
+      (A) 1 mA. (B) 2 mA. (C) 3 mA. (D) 4 mA.'
+    target: Let's think step by step. The torque on a coil in a uniform magnetic field
+      is given by BANI, where B is the magnetic flux density, A is the area of the
+      coil, N is the number of turns, and I is the current. So we have that I = (Torque)/(BAN),
+      or 240e-6/(1200e-6 * 100 * 1) = 2e-3. The answer is (B).
+  - question: 'In an SR latch built from NOR gates, which condition is not allowed
+
+      (A) S=0, R=0 (B) S=0, R=1 (C) S=1, R=0 (D) S=1, R=1'
+    target: Let's think step by step. An SR latch is a set-reset latch; in the case
+      where S=1 and R=1, the circuit has no stable state; instead a race condition
+      will be produced within the circuit, so the device will be in an undefined state.
+      So S=1, R=1 is an illegal question. The answer is (D).
+  - question: 'Two long parallel conductors carry 100 A. If the conductors are separated
+      by 20 mm, the force per meter of length of each conductor will be
+
+      (A) 100 N. (B) 0.1 N. (C) 1 N. (D) 0.01 N.'
+    target: Let's think step by step. The magnetic force-per-length between two current-carrying
+      conductors is given by \mu_0 I_1 I_2 / (2 \pi r), where $r$ is the separation
+      distance and I_1 and I_2 are the currents. Plugging in 100 A for I_1 and I_2,
+      and 20 mm for r, gives 0.1 N. The answer is (B).
+  - question: "In a 2 pole lap winding dc machine , the resistance of one conductor is\
+      \ 2\u03A9 and total number of conductors is 100. Find the total resistance\n\
+      (A) 200\u03A9 (B) 100\u03A9 (C) 50\u03A9 (D) 10\u03A9"
+    target: 'Let''s think step by step. In lap winding, effectively two resistors
+      are connected in parallel, so the actual resistance of each pair is 1 Ohm. Since
+      we have 50 pairs, we get a total resistance of 50 Ohms. The answer is (C).'
+tag: mmlu_flan_cot_fewshot_stem
+include: _mmlu_flan_cot_fewshot_template_yaml
+task: mmlu_flan_cot_fewshot_electrical_engineering