初始化项目，由ModelHub XC社区提供模型

Model: nv-community/Nemotron-Cascade-8B
Source: Original Platform

evaluation/data/mmlu/flan_cot_fewshot/mmlu_college_physics.yaml

@@ -0,0 +1,61 @@
+dataset_name: college_physics
+description: The following are multiple choice questions (with answers) about college
+  physics.
+fewshot_config:
+  sampler: first_n
+  samples:
+  - question: 'A refracting telescope consists of two converging lenses separated by
+      100 cm. The eye-piece lens has a focal length of 20 cm. The angular magnification
+      of the telescope is
+
+      (A) 4 (B) 5 (C) 6 (D) 20'
+    target: Let's think step by step. In a refracting telescope, if both lenses are
+      converging, the focus of both lenses must be between the two lenses, and thus
+      the focal lengths of the two lenses must add up to their separation. Since the
+      focal length of one lens is 20 cm, the focal length of the other must be 80
+      cm. The magnification is the ratio of these two focal lengths, or 4. The answer
+      is (A).
+  - question: 'The muon decays with a characteristic lifetime of about 10^-6 second into
+      an electron, a muon neutrino, and an electron antineutrino. The muon is forbidden
+      from decaying into an electron and just a single neutrino by the law of conservation
+      of
+
+      (A) charge (B) mass (C) energy and momentum (D) lepton number'
+    target: Let's think step by step. Lepton number must be conserved, meaning the
+      total number of leptons minus the number of antileptons. If a muon decays into
+      an electron and a single neutrino, the total lepton number would go from one
+      to two, violating lepton number conservation. The answer is (D).
+  - question: 'One end of a Nichrome wire of length 2L and cross-sectional area A is
+      attached to an end of another Nichrome wire of length L and cross- sectional
+      area 2A. If the free end of the longer wire is at an electric potential of 8.0
+      volts, and the free end of the shorter wire is at an electric potential of 1.0
+      volt, the potential at the junction of the two wires is most nearly equal to
+
+      (A) 2.4 V (B) 3.3 V (C) 4.5 V (D) 5.7 V'
+    target: Let's think step by step. This is a simple voltage divider problem, where
+      the longer wire has a resistance four times that of the shorter end. So the
+      voltage divider ratio is 1 / 5, meaning that the potential in the middle is
+      1.0 V + (8.0 V - 1.0 V) * 1/5 = 2.4 V. The answer is (A).
+  - question: 'A refracting telescope consists of two converging lenses separated by
+      100 cm. The eye-piece lens has a focal length of 20 cm. The angular magnification
+      of the telescope is
+
+      (A) 4 (B) 5 (C) 6 (D) 20'
+    target: Let's think step by step. In a refracting telescope, if both lenses are
+      converging, the focus of both lenses must be between the two lenses, and thus
+      the focal lengths of the two lenses must add up to their separation. Since the
+      focal length of one lens is 20 cm, the focal length of the other must be 80
+      cm. The magnification is the ratio of these two focal lengths, or 4. The answer
+      is (A).
+  - question: 'For which of the following thermodynamic processes is the increase in
+      the internal energy of an ideal gas equal to the heat added to the gas?
+
+      (A) Constant temperature (B) Constant volume (C) Constant pressure (D) Adiabatic'
+    target: 'Let''s think step by step. Heat added to the gas can go into the gases
+      internal energy or work done against an external force. However, if the volume
+      of the gas container is constant, no work will be done (since work is pressure
+      times change in volume). So, at constant volume, all of the heat goes into the
+      internal energy. The answer is (B).'
+tag: mmlu_flan_cot_fewshot_stem
+include: _mmlu_flan_cot_fewshot_template_yaml
+task: mmlu_flan_cot_fewshot_college_physics